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-6a^2+9a+100=0
a = -6; b = 9; c = +100;
Δ = b2-4ac
Δ = 92-4·(-6)·100
Δ = 2481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2481}}{2*-6}=\frac{-9-\sqrt{2481}}{-12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2481}}{2*-6}=\frac{-9+\sqrt{2481}}{-12} $
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